# Answer to Question #10528 in Algebra for Manthan khorwal

Question #10528

If the polynomial p(x)=x4-2x3+3x2-ax+8 is divided by(x-2),it leaves a remainder10.Find the value of a.

Expert's answer

x^4 - 2x^3 + 3x^2 - ax + 8 | x - 2

x^4 - 2x^3 | x^3

+ 3x + (-a-6)

3x^2 - 6x

(-a-6)x + 8

(-a-6)x + 2a +

12

8 - 2a -12

8 - 2a - 12 =

10

2a = -14

a = -7

x^4 - 2x^3 | x^3

+ 3x + (-a-6)

3x^2 - 6x

(-a-6)x + 8

(-a-6)x + 2a +

12

8 - 2a -12

8 - 2a - 12 =

10

2a = -14

a = -7

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