# Answer to Question #10468 in Algebra for Natalie

Question #10468

Number 8

Find the surface area of the bookends shown.

the first one has the numbers shown as 16.5cm 4cm 11cm 16cm. The second one shows 16cm 4 cm 11cm 16.5cm. With 5 sides total I beleive. I beleive that it is the bookends that are shown.

Find the surface area of the bookends shown.

the first one has the numbers shown as 16.5cm 4cm 11cm 16cm. The second one shows 16cm 4 cm 11cm 16.5cm. With 5 sides total I beleive. I beleive that it is the bookends that are shown.

Expert's answer

1) Surface area is 2 areas of triangles with sides (16, 16.5, 4) and 3

rectangles built on these sides of height 11.

2) S(triangle) =

sqrt(p*(p-a)*(p-b)*(p-c))=sqrt(18.25*2.25*14.25*1.75)=32, where

p=(a+b+c)/2

3) S(sides)=(a+b+c)*h=(36.5)*11=401.5;

4) Surface

area=401.5+32+32=465.5

rectangles built on these sides of height 11.

2) S(triangle) =

sqrt(p*(p-a)*(p-b)*(p-c))=sqrt(18.25*2.25*14.25*1.75)=32, where

p=(a+b+c)/2

3) S(sides)=(a+b+c)*h=(36.5)*11=401.5;

4) Surface

area=401.5+32+32=465.5

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