Answer to Question #7251 in Abstract Algebra for Kelcie
Question #7251
Let G be a group and H be a subgroup of G. Define the normalizer of H in G by N(H)={g in G| gHg^(-1)=H}. Prove N(G) is a subgroup of G.
Expert's answer
Need a fast expert's response?
Submit orderand get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment