Answer to Question #7251 in Abstract Algebra for Kelcie
Question #7251
Let G be a group and H be a subgroup of G. Define the normalizer of H in G by N(H)={g in G| gHg^(-1)=H}. Prove N(G) is a subgroup of G.
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Hi Expert, so I wasn't able to try the new version because they closed of the submission portal. Oh well,
but I want to give you my sincerest thank you for helping me throughout this assignment! Honestly, you are an absolute legend! Your line by line explanation was superb and honestly helped me understand most of the concept I learnt during my semester better than my own lecturer! Thank you for consistently helping and being persistent with the versions!
You've honestly been the greatest help and I would have been so lost if it wasn't without your expertise!
So thank you once again!
#207331 on Jun 2018
#207331 on Jun 2018 
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