# Answer to Question #11000 in Abstract Algebra for tianna

Question #11000

Judith works after school at her family's tent company. One of their best selling tents is an A-frame tent that is 4 ft. high and has a rectangular bottom 4ft. wide by 6 ft. long. The sides of the tent are 4.5 ft. long. How much canvas is needed to make the tent?

(Hint: determine the surface area)

(Hint: determine the surface area)

Expert's answer

The tent consists of 5 geometrical figures: 3 rectangles and 2 triangles. The bottom rectangle area is

A1 = width·lenght = 4·6 = 24 ft².

Two other rectangles that make ramps of a tent have area of

A2 = A3 = lenght·√(width²+height²) = 6·√(4²+4²) = 6√32 = 24√2 ft².

Last two triangles that make front and back sides of a tent have area

A4 = A5 = width·height/2 = 6·4/2 = 12 ft².

So, the total area of a needed canvas is

A = A1 + A2 + A3 + A4 + A5 = 24 + 2·24√2 + 2·12 = 48(1+√2) ft².

A1 = width·lenght = 4·6 = 24 ft².

Two other rectangles that make ramps of a tent have area of

A2 = A3 = lenght·√(width²+height²) = 6·√(4²+4²) = 6√32 = 24√2 ft².

Last two triangles that make front and back sides of a tent have area

A4 = A5 = width·height/2 = 6·4/2 = 12 ft².

So, the total area of a needed canvas is

A = A1 + A2 + A3 + A4 + A5 = 24 + 2·24√2 + 2·12 = 48(1+√2) ft².

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