Question #9920

I have the answer but I would like to see how it is done.
An access ramp enters a building 1 m above ground and starts 3 m from the building. How long is the ramp.

Expert's answer

We'll need there Pythagorean theorem.

Denote lenght of the ramp by L. So we obtain

L^2=1^2+3^2=1+9=10

therefore L=sqrt(10)=approximately 3,16 m

Denote lenght of the ramp by L. So we obtain

L^2=1^2+3^2=1+9=10

therefore L=sqrt(10)=approximately 3,16 m

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