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# Answer to Question #170679 in Electrical Engineering for Boama Nana Safo Kantanka

Question #170679
A d.c series motor is connected across a 460 - V supply runs at 500 r/min when the current is 40 A . The total resistance of the armature and field circuits is 0.6 ohms. calculate the torque on the armature in Newton meters.
1
2021-03-11T06:56:21-0500

"Input \\space voltage=460V"

"Speed(N) =500rpm\\implies \\newline\\omega=2\\pi N\/60=52.36 \\space rad\/sec"

"Current(Ia) =40A"

"Total \\space resistance\\space of armature \\space and \\space field=\\newline Rse+Ra=0.6\\Omega"

"We \\space have, \nV=Eb+Ia(Ra+Rse) \\newline\nHence , Back \\space emf (Eb) =460-40\\times0.6=436V"

"We \\space have, \\newline \nEbIa=T\\omega\\implies\\newline Torque(T) \\newline=EbIa\/\\omega=436\\times40\/52.36= 333.08Nm"

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