Question #170588

The resistivity and temperature coefficient of resistance of Evanohm are 800 CM-Ω/ft and

20 x 10-6 /ï‚°C, respectively, at 20ï‚°C. A #40 round wire has a diameter of 0.00314 in. Find the resistance of a 14.79 in long sample of a #40 round Evanohm wire at (a) 20ï‚°C, and

(b) 520ï‚°C.

Expert's answer

**Q170588**

The resistivity and temperature coefficient of resistance of Evanohm are 800 CM-Ω/ft and

20 x 10-6 /ï‚°C, respectively, at 20ï‚°C. A #40 round wire has a diameter of 0.00314 in. Find the resistance of a 14.79 in long sample of a #40 round Evanohm wire at

(a) 20 ^{0}C, and

(b) 52 ^{0}C.

**Solution: **

We are given resistivity, *ρ* = ** ** 800 CM-Ω/ft.

Convert this to Ω.m by using the conversion factor, 1 Ω.m = 60153.49.3 circular mil Ω/ft.

resisitivity in Ω.m =

Temperature coefficient of resistance, *α* = 20 * 10^{-6} / ^{0}C.

**Answer a: **

**To find the resistance of the 14.79-inch long sample of a # 40 Evanohm wire at 20 **^{0}**C. **

Resistance R is related to the length and cross-sectional area of the wire by the relation:

Length of the wire, L

diameter of wire = 0.00314 inch

radius of wire, r = 0.00314 inch/2 = 0.00157 inch.

radius of wire in meter, r

cross sectional Area, A

plug A= 5.00 * 10 ^{-9} m^{2},

resisitivity, *ρ* 1.33 * 10^{-6} Ω.m

and lenght, L = 0.376 meter in the formula, we have

**Answer b : **

**To find the resistance of the 14.79-inch long sample of a # 40 Evanohm wire at 520 **^{0}**C. **

We will use the formula

R = R_{ ref } [ 1 + *α* (T-T_{ref} )]

resistance at 20 ^{0}C will be R_{ ref.}

T_{ ref } = 20 ^{0}C.

T = 520 ^{0}C.

Temperature coefficient of resistance, *α* = 20 * 10^{-6} / ^{0}C.

** **

R = 100.00 Ω [ 1 + 20 * 10^{-6} / ^{0}C. (520 ^{0}C - 20 ^{0}C )]

= 100.00 Ω [ 1 + 20 * 10^{-6} / ^{0}C. * 500 ^{0}C ]

= 100.00 Ω [ 1 + 0.01]

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