Question #169702

a shunt motor is running off a 220 - V supply taking an armature current of 15A , the resistance of the armature circuit being 0.8ohms . calculate the value of the generated e.m.f . jf the flux were suddenly reduced by 10 percent , to what value would the armature current increase momentarily ?

Expert's answer

Given quantities:

"U = 220V" "I = 15A" "R = 0.8\\varOmega"

The electromotive force (e.m.f) is defined as the energy per unit charge that converted from other forms of energy to electrical energy to move a charge across the whole circuit.

"E = \\large\\frac{W}{Q} = \\frac{\\frac{U^2t}{R}}{It}=\\frac{U^2}{IR} = \\frac{220*220}{15*0.8} =" 4033N

"\\varPhi_2 = 0.9\\varPhi_1" "X_L = wL"

"\\large\\frac{L_1I_1}{2} =0.9* \\frac{L_2I_2}{2}"

"\\frac{R_1I_1}{2w} =0.9* \\frac{R_2I_2}{2w}"

"U = 0.9*0.8*I_2 \\to I_2 = 306A"

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