Question #161286

What is the average power dissipation in an RLC series circuit with R=10 ohm, L=0.1 H, C=10 MF, when driven at resonance by 100 V-RMS source

Expert's answer

"P=I_{rms}\\times U_{rms}" ; "Z=\\sqrt{R^2+(\\frac{L}{\\sqrt{LC}}-\\frac{\\sqrt{LC}}{C})^2}"

"I_{rms}=\\frac{U_{rms}}{Z}=" "\\frac{U_{rms}}{\\sqrt{R^2+(\\frac{L}{\\sqrt{LC}}-\\frac{\\sqrt{LC}}{C})}}" "=\\frac{100}{\\sqrt{10^2+(\\frac{0.1}{\\sqrt{0.1\\times10^{-2}}}-\\frac{\\sqrt{0.1\\times10^{-2}}}{10^{-2}})^2}}=10" A

"P=10\\times100=1000" W.

Learn more about our help with Assignments: Electrical Engineering

## Comments

## Leave a comment