Answer to Question #194994 in Civil and Environmental Engineering for Zerick

Question

A 96.6lb is fastened to a cord which is wrapped around a solid cylinder of 3 ft radius weighinh 322lb. The cylinder will raise the weight with an acceleration of 12 ft per seconds? What will be the total bearing reaction?

Answer 1

Newtons Law of Motion for m₁

$T=m_1g+m_1a$

Newtons Law of Motion for m₂

$N=m_2g+T$

$N=m_2g+m_1g+m_1a$

$N(lb)=\frac{m_2g+m_1g+m_1a}{g}$

$N(lb)=m_2+m_1+\frac{m_1a}{g}$

$N(lb)=322lb+96.6lb+\frac{96.6*12}{32.174}lb$

$N(lb)=454.62g lb =454.62*32.174lbft/s^2=14627.236 pound-force$