Question #184955

Ice has a density of 0.92 g/cm³ and seawater has a density of 1.04 g/cm³. Determine the total volume of a floating iceberg if 30 m³ is above the seawater.

Expert's answer

Provided that the

Density of ice is ="0.92 g\/m^3"

Density of sea water "=" "1.04 g\/cm^3"

Volume of Ice berg above water "= 30 m^3 or 3.0 \\times 10^7 cm^3"

If v' is the volume of ice berg immersed in water

then as per the law of floatation = "\\frac{v'}{V} = \\frac{density of ice }{density of sea water}"

"=\\frac{v'}{V}= \\frac{0.92}{1.04}= 0.8846"

v' = 0.88361 V

Volume of the iceberg over the surface of sea water is obtained by:

V(1 - 0.8846) = "3.0 \\times 10^7 cm^3"

"V = \\frac{3.0 \\times 10^7 cm^3}{1-0.8846} = 2.59965 \\times 10^8 cm^3"

V= "259.9653 m^3"

Learn more about our help with Assignments: Engineering

## Comments

## Leave a comment