A hydraulic press has a small piston of diameter 2 cm. If a force of 60 N is applied to the smaller piston, a force of 300 N is exerted on the larger piston. What is the diameter of the larger piston?
Pascal's Principle: "F1\/A1=F2\/A2"
r= (0.224x100) cm
Diameter= (2.24cm x2)