Answer on Physical Chemistry Question for Sandeepan dhar chowdhury
(i) correspond to light of frequency 3 x 10^15 Hz.
(ii) Have wavelength of 0.50A
E = hν/c = hc/ λ, where h -is a Planck constant, c - the speed of the light, ν - the frequency, λ - the wavelength.
(i) E = 6.62 x 10-34 * 3 x 1015 / 3 x 108 = 6.62 x 10-27 J.
(ii) E = 6.62 x 10-34 *3 x 108 /0.5 x 10-10 = 3.972 x 10-15 J.
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