Question #3078

The equation of reaction between potassium and water.

2K + 2H[sub]2[/sub]O(1) --> 2KOH(aq) + H[sub]2 [/sub]

Find the mass of potassium needed to produce 1.505 x 10[sup]24[/sup] hydorgen molecule.

2K + 2H[sub]2[/sub]O(1) --> 2KOH(aq) + H[sub]2 [/sub]

Find the mass of potassium needed to produce 1.505 x 10[sup]24[/sup] hydorgen molecule.

Expert's answer

Let's find the amount of moles of H_{2}:

1.505x1024/6.022 x 10^{23} = 2.5 mol.

From the ballanced equation

2K + 2H_{2}O(1) -> 2KOH(aq) + H_{2}

we can see that potassium has twice mol than H_{2}.

v(H_{2}) = 5 mol.

The mass of the potassium is 39 g/mol/ * 5 mol = 195 g.

1.505x1024/6.022 x 10

From the ballanced equation

2K + 2H

we can see that potassium has twice mol than H

v(H

The mass of the potassium is 39 g/mol/ * 5 mol = 195 g.

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