Answer to Question #29668 in Physical Chemistry for adeja
How many grams of water vapor (H2O) are in a 10.2 liter sample at 0.98 atmospheres and 26°C? Show all work used to solve this problem.
For solving that task we shall use the equation: pV = nRT, where p-pressure, V-volume, n - amount of moles, n - gas constant (n = 0.080206) n = pV/RT The amount of moles can be found by the equation: n = m/M where m - mass, M - molar mass So the mass could be calculated as: m = n*M M(H2O) = 18 grams/mole n(H2O) = 0.98*10.2/0.08206*(26 + 273) = 0.43 moles m(H2O) = 0.43*18 = 7.3 grams
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