# Answer to Question #29621 in Physical Chemistry for Casey

Question #29621

If 4.50 g of methane gas (CH4) is introduced into an evacuated 2.00 L container at 35 degress C, what would be the pressure in atmosphere ?

Expert's answer

To calculate the pressure we can use the formula:

PV = nRT

where

P - the pressure

n - amount of substance

V - the volume

T - the temperature

R - universal gas constant

P = nRT / V = (4.50 g CH

PV = nRT

where

P - the pressure

n - amount of substance

V - the volume

T - the temperature

R - universal gas constant

P = nRT / V = (4.50 g CH

_{4}/ 16.04257 g CH_{4}/mol) x (0.08205746 L atm/K mol) x (35 + 273 K) / (2.00 L) = 3.54 atm**Answer:**3.54 atmNeed a fast expert's response?

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