Answer to Question #22311 in Physical Chemistry for asma

Question #22311
the formation of urea (NH4NOCNH4) from the Ammonium isocyanate (CH4N2O) have been prepared(NH4CNO------.>NH2CONH2). at the begining 22.9 g from Ammonium isocyanate has been solved in water so 1.00 L (LITER) from the Solution prepared. 1) order of reaction? 2)rate constant (K)? 3)the mass of Ammonium isocyanate that has been remained after 300 minutes? T/min 0 20 50 65 150 m(urea) 0 7 12.1 13.8 17.7 thank u
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2013-01-18T04:41:17-0500
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