Answer to Question #22311 in Physical Chemistry for asma

Question

the formation of urea (NH4NOCNH4) from the Ammonium isocyanate (CH4N2O) have been prepared(NH4CNO------.>NH2CONH2).
at the begining 22.9 g from Ammonium isocyanate has been solved in water so 1.00 L (LITER) from the Solution prepared.
1) order of reaction?
2)rate constant (K)?
3)the mass of Ammonium isocyanate that has been remained after 300 minutes?
T/min 0 20 50 65 150
m(urea) 0 7 12.1 13.8 17.7

thank u