Question #22236

. determine the mass of water that absorbs 1234 J of heat and undergoes a temperature change of 33.4oC.

Expert's answer

Heat is evaluated asQ=c*m*(t_{2}-t_{1})

where m is mass and c is specific heat capacity.

In our case t_{2}-t_{1}=33.4. so we find mass

m = Q/(c*(t_{2}-t_{1})) = 1234/(4200*33.4) = 0.0088 kg = 8.8g

mass of water is 8.8 g

where m is mass and c is specific heat capacity.

In our case t

m = Q/(c*(t

mass of water is 8.8 g

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