Question #21207

Q. 50g CaCO3 will react with ......g of 20% HCl by weight-

(i) 36.5 gm (ii)73 gm (iii)109.5 gm (iv)182.5 gm

(i) 36.5 gm (ii)73 gm (iii)109.5 gm (iv)182.5 gm

Expert's answer

Equation of the reaction between calcium carbonate and hydrochloric acid

2HCl (l) + CaCO_{3} (s) → CaCl_{2} (aq) + H_{2}O (l) + CO_{2} (g)

The molar mass of CaCO_{3} is 100 g/mol. Thus the amount of 50g of CaCO_{3} is 0.5 mol.

One mol of calcium carbonate reacts with two mol of hydrochloric acid. Thus, 0.5 mol of CaCO_{3} reacts with 1 mol of HCl.

The molar mass of HCl is 36.5 g/mol. The mass of 1 mol HCl is 36.5 g.

The concentration of HCl in the solution by weight is

w(HCl) = m(HCl) / m(solution)

Thus, the mass of the 20% solution of 36.5 g of HCl is

m(HCl solution) = m(HCl) / w(HCl) = 36.5 g / 0.2 = 182.5 g.

Answer: (iv) 182.5 g

50g CaCO3 will react with 182.5 g of 20% HCl by weight.

2HCl (l) + CaCO

The molar mass of CaCO

One mol of calcium carbonate reacts with two mol of hydrochloric acid. Thus, 0.5 mol of CaCO

The molar mass of HCl is 36.5 g/mol. The mass of 1 mol HCl is 36.5 g.

The concentration of HCl in the solution by weight is

w(HCl) = m(HCl) / m(solution)

Thus, the mass of the 20% solution of 36.5 g of HCl is

m(HCl solution) = m(HCl) / w(HCl) = 36.5 g / 0.2 = 182.5 g.

Answer: (iv) 182.5 g

50g CaCO3 will react with 182.5 g of 20% HCl by weight.

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