Question #21043

A gas that has a volume of 28 liters, a temperature of 45 °C, and an unknown pressure, has its volume increased to 34 liters and its temperature decreased to 35 °C. If I measure the pressure after the change to be 2.0 atm, what was the original pressure of the gas?

Expert's answer

For answering this question,you need to usenext equation

P_{1}V_{1}/T_{1} = P_{2}V_{2}/T_{2}

P_{1} = P_{2}V_{2}T_{1}/T_{2}V_{1}

P_{1} = 2.0 * 34 * 45 / 35* 28 = 3.12 atm

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## Comments

Roo30.04.13, 07:41You need tro convert Celsius to Kelvin first though. So P1 = (2 atm)(34L)(318K)/(28L)(308K) --> 2.507 atm (not 3.12)

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