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Answer to Question #21043 in Physical Chemistry for Roy Fonda
Question #21043
A gas that has a volume of 28 liters, a temperature of 45 °C, and an unknown pressure, has its volume increased to 34 liters and its temperature decreased to 35 °C. If I measure the pressure after the change to be 2.0 atm, what was the original pressure of the gas?
Expert's answer
For answering this question,you need to usenext equation
P1V1/T1 = P2V2/T2
P1 = P2V2T1/T2V1
P1 = 2.0 * 34 * 45 / 35* 28 = 3.12 atm
P1V1/T1 = P2V2/T2
P1 = P2V2T1/T2V1
P1 = 2.0 * 34 * 45 / 35* 28 = 3.12 atm
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Comments
You need tro convert Celsius to Kelvin first though. So P1 = (2 atm)(34L)(318K)/(28L)(308K) --> 2.507 atm (not 3.12)
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