Question #30674

How many moles of P4 would you need to produce 34 grams of PH3?
P4 (s) + 6H2 (g) ____> 4PH3 (g)

Expert's answer

First of all we can find the amount of substance of PH_{3}. We can use the formula

n = m/M

where

n - the amount of substance

m - the mass

M - the molar mass, which can be calculated as follows: M(PH_{3}) = Ar(P) +3*(H) = 31+ 3*1 = 34 g/mol

n(PH_{3}) = 34 g / 34 g/mol = 1 moles

According the equation

P_{4}(s) + 6H_{2}(g) ---> 4PH_{3}(g)

we can find the amount of substance of P_{4}:

n(P_{4}) = n(PH_{3})/4 = 1/4 = 0.25 moles

Answer: 0.25 moles

n = m/M

where

n - the amount of substance

m - the mass

M - the molar mass, which can be calculated as follows: M(PH

n(PH

According the equation

P

we can find the amount of substance of P

n(P

Answer: 0.25 moles

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