Answer to Question #286204 in Organic Chemistry for Nick

Question

The measured integration trace gives the ratio 0.90 to 0.45 to 2.70 to 1.35 for the peak at &= 1.52 , 1.39 , 1.21 and 0.93 , respectively. Use the table below to answer the following questions.

• chemical shift (ppm) 0.5-5.0 and Description of H atom is ROH.
• chemical shift (ppm) 0.7-1.3 and description of H atom is RCH3.
• chemical shift (ppm)1.4-1.7 and description of H atom is R3CH.
• chemical shift (ppm) 1.2 -1.4 and description of H atom is R2CH2.
• chemical shift (ppm) is 2.1-2.6 and the description of H atom is RCH2CO.
• chemical shift (ppm) is 3.1-4.2 and description of H atom is RCH2Br or RCH2CI.
• chemical shift (ppm) is 9.0 -10.0 and the description of H atom is RCOH.
• chemical shift (ppm) is 10.0-12.0 and the description of H atom is RCOOH

Questions :

c) what is the ratio of the number of each type of proton?(1 mark)

d) The peak at &= 1.52 and &=0.93 arise from the presence of a single alkyl group. Identify this group and explain the splitting pattern( 6 marks detailed explanation).

Answer 1

(12-10)(5-0.5)

= 2×4.5

= 9

d) alkene