Answer on Organic Chemistry Question for mimi
ANS: I calculated this to be 16.7:1 (based on the fact that i need 12.5 O2 for on 1 of C8H18 and O2 is only 21% of air.
my question is the next part.
determine the excess air factor if a dry volumetric analysis of the products of the fuel is C02(9%) C0(2%) N2(89%).
C8H18 + 12.5O2 ---> 8CO2 + 9H2O , where CO2 is produced
In your case one of the products is CO. It means that O2 was in shortage, so if there is no O2 in products, but only CO2 (9%), CO (2%), N2 (89%), air was not in excess.
Need a fast expert's response?Submit order
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!