Answer to Question #21605 in Organic Chemistry for Sadaam Ahmed
a. Calculate the concentration of chloride ions.
b. If the original substance was sodium chloride, NaCl (s), what mass of it was dissolved in the volumetric flask?
n(AgCl) = 0.765 g / M(AgCl)
M(AgCl) = 108 + 35.5 = 143.5 g/mol
n(AgCl) = 0.765 g /143.5 g/mol = 0.00533 mol
n(AgCl) = chloride ions = 0.00533 mol
C(chloride ions) = n/V
C(chloride ions) = 0.00533 mol/1l = 0.00533 mol/ L (a)
n(NaCl) = 0.00533 mol
M(NaCl) = 23 + 35.5 = 58.5 g/mol
m(NaCl) = 0.00533 mol * 58.5 g/mol = 0.3115 g (b)
a) 0.00533 mol/ L
b) 0.3115 g
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