Answer to Question #92804 in Inorganic Chemistry for uma

Question #92804
4dm3 of h2s reacts with 10dm3 of o2 at constant presssure and temperature what is the final volume?
1
Expert's answer
2019-08-19T02:05:41-0400

2H2S + 3O2 = 2H2O + 2SO2


H2S is a limiting reagent and 2 moles of it will burn out in 3 moles of O2. 3 moles of O2 is 6 dm3, which means 4 dm3 of oxygen will remain in products as an extra.

By stoichiometry, 2 moles of each product was produced, that means 4 dm3 H2O and 4 dm3 of SO2 were produced.

Final volume = 4 dm3 (O2 not used) + 4dm3 (SO2) + 4 dm3 (H2O) = 12 dm3

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

Ask Your question

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS