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Answer to Question #3093 in Inorganic Chemistry for sweet
Question #3093
13.4 g of a sample of unstable hydrated salt: Na2SO4. xH20 was found to contain 6.3g of water. Determine the number of water of crystallization
Expert's answer
The molar mass of the salt is m(Na2SO4* xH2O) = 2*23+32+16*4 + x (2 + 16) = 142 + x*18 [g/mol]
Then let's construct the proportion:
13.4 / 6.3 = (142 + 18x)/18x
13.4 * 18x = (142 + 18x) * 6.3
241.2x = 894.6 + 113.4x
127.8x = 894.6
x = 7
Na2SO4* 7H2O
Then let's construct the proportion:
13.4 / 6.3 = (142 + 18x)/18x
13.4 * 18x = (142 + 18x) * 6.3
241.2x = 894.6 + 113.4x
127.8x = 894.6
x = 7
Na2SO4* 7H2O
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Comments
Dear Madhav, You're welcome. We are glad to be helpful. If you liked our service please press like-button beside answer field. Thank you!
Thank you sir. This will really help me
It is formed by fact that we know the total mass of compound and how much water it contains. Then it is clear the proportion of water mass in compound to the total mass will be the same as the ratio of molar mass of water to the total molar mass of compound.
Pls tell how is this proportion formed
You're welcome. We are glad to be helpful. If you liked our service please press like-button beside answer field. Thank you!
Thanks... I needed that.
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