Question #29709

How many mLs of H2 gas, collected by water displacement, are produced by the reaction of 0.500 g of Mg metal with an excess of HCl, at an atmospheric pressure of 750 torr and a temperature of 25.0 C? The vapor pressure of water at 25.0 C is 23.8 torr.

Expert's answer

Thechemical equation of this process is

2Mg + 2HCl = MCl_{2} + H_{2}

n(Mg) = 0.5 g / 24 g/moles = 0.021moles

n(H_{2}) = 0.021moles *1/2 = 0.0105moles

pressure of dry H_{2} gas = 750 torr - 23.8torr = 726.2 torr

from the equation

PV = nRT

V = nRT/P

V(H_{2}) = 0.0105moles * 8.314 * 298 K / 96 820 Pa = 0.27 mLAnswer: 0.27 mL

2Mg + 2HCl = MCl

n(Mg) = 0.5 g / 24 g/moles = 0.021moles

n(H

pressure of dry H

from the equation

PV = nRT

V = nRT/P

V(H

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