Answer to Question #29530 in Inorganic Chemistry for aayushi
4% decrease---- now weight is 0.96 g(Ge + B)----0.04 g missing
0.04 missing-------- (0.04-0.00015)g Ge missing------(0.04-0.00015)/72.61 moles
Ge missing=5.488*10^-4 moles
Boron replaced= 1.5*10^-4 g = (1.5*10^-4)/10 moles
equivalently replaced = 3/4((1.5*10^-4)/10) moles of Ge ( Valency of B is 3 and
Ge is 4)
= 0.1125*10^-4 moles of Ge
% of Missing vacancies filled by B atoms = 0.1125*100/5.488 = 2.05 %
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The decrease of the crystal weight (4%) consists of two components: 1) loss of Ge and 2) acquiring of B which is lighter than Ge (so it is the same effect as loss). So we have two negative effects which together make a contribution of -4%. If we deduct the part of B we will get the part of Ge that was lost.
in 0.96g quantity both Ge and B are present but in 0.04 missing quantity of crystal how u calculate the weight of Ge by 0.04-0.00015