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Answer to Question #25290 in Inorganic Chemistry for Katie Hopkins

Question #25290
A sample of nitrogen gas exerts a pressure of 9.80 atm at 32 °C. What would its temperature be (in °C) when its pressure is increased to 11.2 atm?


Expert's answer
Modified Clapeyron-Mendeleev law equation can be used for answering this question:
PV=nRT
P1V1=nRT1
P2V2=nRT2

P1/T1=P2/T2
T2=P2/(P1/T1)

So the answer is T2=11.2 atm*32 °C /9.80 atm = 36,6 C

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