# Answer to Question #25168 in Inorganic Chemistry for Elizabeth

Question #25168

A balloon containing 0.56 mol of helium has a volume of 10.0 L. What volume will the balloon occupy if helium is lost and only 0.21 mol remain?

Expert's answer

According to the ideal gas law

pV

pV

p (pressure), T(temperature), R (universal gas constant) - don't change

V

n

(pV

V

After helium is lost the volume is

V

V

Answer: V

pV

_{1}= n_{1}RT - at the beginningpV

_{2}= n_{2}RT - after part of helium is lostp (pressure), T(temperature), R (universal gas constant) - don't change

V

_{1}, V_{2}- volumesn

_{1}, n_{2}- moles(pV

_{1}/pV_{2}) = (n_{1}RT)/(n_{2}RT)V

_{1}/V_{2}= n1/n2After helium is lost the volume is

V

_{2}= (V_{1}n_{2})/n1V

_{2}= (10.0 x 0.21)/ 0.56 = 3.75 LAnswer: V

_{2}= 3.75 L
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