Question #25168

A balloon containing 0.56 mol of helium has a volume of 10.0 L. What volume will the balloon occupy if helium is lost and only 0.21 mol remain?

Expert's answer

According to the ideal gas law

pV_{1} = n_{1}RT - at the beginning

pV_{2} = n_{2}RT - after part of helium is lost

p (pressure), T(temperature), R (universal gas constant) - don't change

V_{1}, V_{2} - volumes

n_{1}, n_{2} - moles

(pV_{1}/pV_{2}) = (n_{1}RT)/(n_{2}RT)

V_{1}/V_{2} = n1/n2

After helium is lost the volume is

V_{2} = (V_{1}n_{2})/n1

V_{2} = (10.0 x 0.21)/ 0.56 = 3.75 L

Answer: V_{2} = 3.75 L

pV

pV

p (pressure), T(temperature), R (universal gas constant) - don't change

V

n

(pV

V

After helium is lost the volume is

V

V

Answer: V

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