Question #24351

For the following reaction, 14.8 grams of sulfur are allowed to react with with 19.9 grams of carbon monoxide.
sulfur (s) + carbon monoxide (g) sulfur dioxide (g) + carbon (s)
What is the maximum amount of sulfur dioxide that can be formed?

Expert's answer

S + 2CO = SO_{2} + 2C

First, look for the amount of substance of sulfur:

n(S) = m / M

n(S) = 14.8 g/32 g / mol = 0.4625 mol

n(CO) = m (CO) / M (CO)

M(CO) = 12 + 16 = 28 g/mol

n(CO) = 19.9 g/28 g/mol = 0.71 mol

S in excess, so for calculating we take CO:

n(SO_{2}) = n(CO)/2 = 0.71 mol/2 = 0.355 mol

m(SO_{2}) = M(SO_{2})*n(SO_{2})

M(SO_{2}) = 32 + 16*2 = 64 g/mol

m(SO_{2}) = 64 g/mol * 0.355 mol = 22.74 g

First, look for the amount of substance of sulfur:

n(S) = m / M

n(S) = 14.8 g/32 g / mol = 0.4625 mol

n(CO) = m (CO) / M (CO)

M(CO) = 12 + 16 = 28 g/mol

n(CO) = 19.9 g/28 g/mol = 0.71 mol

S in excess, so for calculating we take CO:

n(SO

m(SO

M(SO

m(SO

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