Answer to Question #24232 in Inorganic Chemistry for Ileana
How many moles of H2 can be generated from .57 mol Al and .37 mol NaOH in excess water?.
For answering your questions you need to considerthe next equation:
2Al + 2NaOH + 6H2O = 2Na[Al(OH)4] + 3H2
Al is in excess, so only 0.37 mol of it will react.
And about H2. Amount if it is 0.37 * 3/2 = 0.555 moles