Answer to Question #19697 in Inorganic Chemistry for Farhat

Question

A 35.0 g block of copper at 350.0 degrees celcius is added to a beaker containing 525 g of water at 35.0 degrees celcius. What is the final temperature of water?

Answer 1

Let us denote
m_c - mass of copper = 35 g
c_c - specific heat capacity of copper = 385 J/(kg*K)
t_c - temperature of copper = 350 C = 623 K
m_w - mass of water = 525g
c_w - specific heat capacity of water = 4200 J/(kg*K)
t_w - temperature of water = 35 C = 308 K

T - final temperature.
we can write

m_c*c_c*(t_c-T) = m_w*c_w*(T-t_w)

Hence
T = (m_c*t_c*c_c + m_w*t_w*c_w) / (m_w*c_w + m_c*t_c) = 310K = 37 degrees celcius