Calculate the molar mass of barium citrate.
Ba(NO3)2
Molar mass of Ba = 137.327
Molar Mass of N = 14.0067
= 14.0067 × 2 = 28.0134
Molar Mass of O = 15.999
= 15.999 × 6 = 95.994
= 137.327 + 28.0134 + 95.994
= 261.3344g/mol
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