Answer to Question #179492 in Inorganic Chemistry for Samridhi

Question #179492

A sample of water contains: suspended matter = 100 mg; Ca(NO3)2 = 16.4 mg/L; MgSO4 = 24 mg/L; MgCl2 = 19 mg/L; NaOH = 40 mg/L and KOH = 56 mg/L. Calculate temporary, permanent and total hardness of the water sample in PPM. (Atomic masses of Na = 23; Mg = 24; K = 39 and Ca = 40).


1
Expert's answer
2021-04-08T12:11:52-0400

Total hardness =3 12.5 ppm


Permanent hardness =208.33ppm


Temporary hardness = total hardness – permanent hardness= 312.5 – 208.33 = 104.17ppm


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