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# Answer to Question #159135 in Inorganic Chemistry for Daniella

Question #159135

Calculate the mass of pure sodium chloride that will yield enough hydrogen chloride gas to neutralize 25cm3 of 0.5M potassium trioxocarbonate (V) solution

1
2021-01-28T05:47:57-0500

"\\textsf{no. of moles of } K_2CO_3 = c \u00d7 V = \\\\\n0.5 \u00d7 \\dfrac{25}{1000} = 0.0125 \\textsf{ moles}"

"2HCl + K_2CO_3 \\to 2KCl + H_2CO_3"

from the reaction above, 2 moles of HCl reacts 1 mole of K2CO3.

This means that 0.025 moles of HCl reacts 0.0125 moles of K2CO3.

"2NaCl + H_2SO_4 \\to NaSO_4 + 2HCl"

from the reaction above, 2 moles of NaCl produces 2 moles of HCl.

This means that 0.025 moles of NaCl reacts with 0.025 moles of H2SO4.

1 mole of NaCl is 58.5g

therefore, 0.25 moles of NaCl is 14.625g

therefore, 14.625g of NaCl will yield enough HCl to neutralize 25cm3 of 0.5M K2CO3.

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