Answer to Question #14344 in Inorganic Chemistry for hirwa

Question

How many grams of Cu and what volume of O2 gas will be obtained if 18.4 ampere electric current is passed through the electrolytic cell of CuSO4for 1 hour and 42 minutes between graphite electrodes at 208 K temperature and 1 bar pressure?
(Cu=63.5u O=16u) How to calculate?

Answer 1

m = k · Q,
Q = I · t.
k=Mw/F=Mw/96500

m=Mw/96500 * I *
t

m(Cu)=63.5/96500 *18,4*6120=74.099
g

m(O2)=32/96500*18.4*6120=37.34
g

PV=m/Mr*RT

V=(37.34/32)*8.31*208 /105=19.21 L