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Answer on Inorganic Chemistry Question for shashi kumar

Question #14027
a reaction of second order with respect to a reactant.how is the rate of reaction affected if the concentration of the reactants is reduced half? what is the unit of rate constant of such reaction?
Expert's answer
Look in your text book for the 2nd order chemical reaction (shown below) and plug n chug fake numbers into [A], the concentration, t (time in seconds), and
A0 and see what happens to k (the rate of the reaction) when you double and reduce A by half.

1/[A] = kt + 1/A0

Rate = k[A]^2

mol/sec = k(mol/L)^2 = k(mol2/L2)

k = L2/mol-sec

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