Question #134940

The highest energy electrons in an atom Q have the principal quantum number n = 4 and the angular quantum number l = 0. What is the maximum number of electrons present in atom Q?

Expert's answer

We are interested in the **maximum number of electrons** in all the energy levels

n=4 and l=0

That means that we have for;

s; l=0

p; l=1

d; l=2

f; l=3

Thus when n=4 and l=0, then the highest orbital is 4s which has a maximum of** 2 electrons**.

If we now re-write the electron configuration of Q, we will have;

1s^{2}, 2s^{2}, 2p^{6}, 3s^{2}, 3p^{6}, 3d^{10}, 4s^{2}

Thus the total number of electrons is 2+2+6+2+6+10+2 = **30 electrons**

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