Answer to Question #125392 in Inorganic Chemistry for beena

Question

if 30 g of calcium carbonte react with 20 g of HCl, how many grams of CO2 will produce?

Answer 1

A balanced chemical equation for the reaction is;

$CaCO_3+2HCl\to CaCl+CO_2+H_2O$ .The mole ratio of $CaCO_3$ and $CaCl$

${1mol CaCO_3}\over1molCaCl_2$ and $1mol CaCl_2\over1molCaCO_3$

Mole ratio of $HCl$ and $CO_2$

$2mol HCl\over 1mol CO_2$ and $1molCO_2\over 2HCl$

Mole ratio of $CaCO_3$ and $HCl$

$1molCaCO_3\over 1mol HCl$ and $2mol HCl\over 1mol CaCO_3$

Moles of each reactant $=$ The given molar masses

$30.0gCaCO_3$ $*$ $1molCaCO_3\over100.1g CaCO_3$

$=0.30molCaCO_3$

$20.0gHCl$ $*$ $1mol HCl\over 36.5gHCl$

$=0.548molHCl$

The mass of $CO_2$

$0.30mol CaCO_3$ $*$ $1mol CO_2\over 1mol CaCO_3$ $*$ $44.01gCO_2\over 1mol CO_2$

$=13.203g CO_2$

Mass of $HCl$

$0.548mol HCl$ $*$ $1mol CaCO3\over 2mol HCl$ $*$ $100.1g CaCO_3\over 1mol CaCO_3$ $=27.4g CaCO_3$

Mass of $CO_2$ $= 27.4g-13.204g$

$=14.197gCO_2$