Answer to Question #125230 in Inorganic Chemistry for Kenny

Question #125230
A 30 cm3 sample of nitrogen was reacted with a 60 cm3 sample of fluorine according to the equation
What is the volume of the gas mixture after the reaction, at constant temperature and pressure?
1
Expert's answer
2020-07-08T08:24:16-0400

The equation is

N2(g) + 3F2(g) --> 2NF3(g)

The mole (and volume) N2 : F2 ratio according to the equation is 1 : 3.

The actual ratio is 30 : 60 or 1 : 2, hence F2 is the limiting reactant.

To calculate the volume of a gas mixture after the reaction, the volume of NF3 and remaining N2 should be determined.

V(NF3) = 2/3 x V(F2) = 40 cm3.

According to the equation, the volume of N2 that reacted is 1/3 x V(F2) = 20 cm3.

Vremaining(N2) = Vtotal(N2) - Vreacted(N2)= 30 - 20 = 10cm3.

Vmixture = 40 + 10 = 50 cm3.

Answer: 50 cm3

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Comments

Assignment Expert
26.11.20, 21:01

Dear Max, Questions in this section are answered for free. We can't fulfill them all and there is no guarantee of answering certain question but we are doing our best. And if answer is published it means it was attentively checked by experts. You can try it yourself by publishing your question. Although if you have serious assignment that requires large amount of work and hence cannot be done for free you can submit it as assignment and our experts will surely assist you.

max
24.11.20, 17:28

how come is f2 the limiting reactor

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