Question #125230

A 30 cm3 sample of nitrogen was reacted with a 60 cm3 sample of fluorine according to the equation

What is the volume of the gas mixture after the reaction, at constant temperature and pressure?

What is the volume of the gas mixture after the reaction, at constant temperature and pressure?

Expert's answer

The equation is

N_{2}(g) + 3F_{2}(g) --> 2NF_{3}(g)

The mole (and volume) N_{2} : F_{2} ratio according to the equation is 1 : 3.

The actual ratio is 30 : 60 or 1 : 2, hence F_{2} is the limiting reactant.

To calculate the volume of a gas mixture after the reaction, the volume of NF_{3} and remaining N_{2} should be determined.

V(NF_{3}) = 2/3 x V(F_{2}) = 40 cm^{3}.

According to the equation, the volume of N_{2} that reacted is 1/3 x V(F_{2}) = 20 cm^{3}.

V_{remaining}(N_{2}) = V_{total}(N_{2}) - V_{reacted}(N_{2})= 30 - 20 = 10cm^{3}.

V_{mixture} = 40 + 10 = 50 cm^{3}.

**Answer: **50 cm^{3}

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Assignment Expert26.11.20, 21:01Dear Max, Questions in this section are answered for free. We can't fulfill them all and there is no guarantee of answering certain question but we are doing our best. And if answer is published it means it was attentively checked by experts. You can try it yourself by publishing your question. Although if you have serious assignment that requires large amount of work and hence cannot be done for free you can submit it as assignment and our experts will surely assist you.

max24.11.20, 17:28how come is f2 the limiting reactor

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