Answer to Question #125230 in Inorganic Chemistry for Kenny

Question #125230

A 30 cm3 sample of nitrogen was reacted with a 60 cm3 sample of fluorine according to the equation
What is the volume of the gas mixture after the reaction, at constant temperature and pressure?

Expert's answer

The equation is

N₂(g) + 3F₂(g) --> 2NF₃(g)

The mole (and volume) N₂ : F₂ ratio according to the equation is 1 : 3.

The actual ratio is 30 : 60 or 1 : 2, hence F₂ is the limiting reactant.

To calculate the volume of a gas mixture after the reaction, the volume of NF₃ and remaining N₂ should be determined.

V(NF₃) = 2/3 x V(F₂) = 40 cm³.

According to the equation, the volume of N₂ that reacted is 1/3 x V(F₂) = 20 cm³.

V_remaining(N₂) = V_total(N₂) - V_reacted(N₂)= 30 - 20 = 10cm³.

V_mixture = 40 + 10 = 50 cm³.

Answer: 50 cm³

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26.11.20, 21:01

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max

24.11.20, 17:28

how come is f2 the limiting reactor

Answer to Question #125230 in Inorganic Chemistry for Kenny

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