The equation is
N2(g) + 3F2(g) --> 2NF3(g)
The mole (and volume) N2 : F2 ratio according to the equation is 1 : 3.
The actual ratio is 30 : 60 or 1 : 2, hence F2 is the limiting reactant.
To calculate the volume of a gas mixture after the reaction, the volume of NF3 and remaining N2 should be determined.
V(NF3) = 2/3 x V(F2) = 40 cm3.
According to the equation, the volume of N2 that reacted is 1/3 x V(F2) = 20 cm3.
Vremaining(N2) = Vtotal(N2) - Vreacted(N2)= 30 - 20 = 10cm3.
Vmixture = 40 + 10 = 50 cm3.
Answer: 50 cm3
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how come is f2 the limiting reactor