Answer to Question #125217 in Inorganic Chemistry for Kenny

Question #125217
Two sealed flasks with the same volume are left side by side. Flask A contains 4.0 × 10−3 mol of methane.
Flask B contains 340 mg of a different gas.
Both gases are at the same temperature and pressure. Which gas could be in Flask B?
1
Expert's answer
2020-07-07T14:20:17-0400

n1=n2=0,004mol

m2=0,34g

M2 = m2/n2 = 0,34/0,004 = 85 g/mol

If the temperature is higher then 40°C, gas in 2-th flask is a CH2Cl2.

Answer CH2Cl2.



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