Answer to Question #125217 in Inorganic Chemistry for Kenny

Question

Two sealed flasks with the same volume are left side by side. Flask A contains 4.0 × 10−3 mol of methane.
Flask B contains 340 mg of a different gas.
Both gases are at the same temperature and pressure. Which gas could be in Flask B?

Answer 1

n1=n2=0,004mol

m2=0,34g

M2 = m2/n2 = 0,34/0,004 = 85 g/mol

If the temperature is higher then 40°C, gas in 2-th flask is a CH₂Cl_2.

Answer CH₂Cl_2.