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Answer to Question #120362 in Inorganic Chemistry for Jamie koonoolal
Question #120362
Show by means of energy orbital diagrams how sodium hexachlorovanadate(II) exists as a
magnetic transition metal compound whereas tris(ethylenediammine)nickel(IV) nitrate is
unaffected by a magnetic field.
magnetic transition metal compound whereas tris(ethylenediammine)nickel(IV) nitrate is
unaffected by a magnetic field.
Expert's answer
Solution.
1.
Na4[VCl6]
Z(V) = 2+
Cl - is a weak field ligand, so such a complex will be high-spin.
According to the graph, the magnetic moment of this complex is equal to 1.5.
2.
[Ni(en)3](NO3)4
Z(Ni) = 4+
Ethylenediamine(en) is a strong field ligand, hence this complex is low-spin.
According to the graph, the magnetic moment of this complex is equal to 0.
Answer:
The first complex is a compound of a magnetic transition metal, since the structure of this complex has unpaired electrons that cause the magnetic moment of the complex.
The second complex is a compound of a non-magnetic transition metal, since there are no unpaired electrons in the structure of this complex that would cause the magnetic moment of the complex.
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