Z(V) = 2+
Cl - is a weak field ligand, so such a complex will be high-spin.
According to the graph, the magnetic moment of this complex is equal to 1.5.
Z(Ni) = 4+
Ethylenediamine(en) is a strong field ligand, hence this complex is low-spin.
According to the graph, the magnetic moment of this complex is equal to 0.
The first complex is a compound of a magnetic transition metal, since the structure of this complex has unpaired electrons that cause the magnetic moment of the complex.
The second complex is a compound of a non-magnetic transition metal, since there are no unpaired electrons in the structure of this complex that would cause the magnetic moment of the complex.
Dear damon Questions in this section are answered for free. We work on all questions and publish answers after verification. There is no guarantee of answering certain question but we are doing our best. Although if you have serious assignment that requires large amount of work and hence cannot be done for free you can submit it as assignment and our experts will surely assist you.
Calcium hydroxide and calcium sulfate are both used to prepare a saturated solution, S. Both solids are only sparingly soluble, and the pH of S is found to be 11.6. (i) Given that the Ksp for calcium hydroxide is 4.0 x 10-5 and the Ksp for calcium sulfate is 2.5 x 10-5 , determine the concentration of sulfate ions present in S.
53.8 grams of a complex, diamminebis(oxalato)cobaltate(II), were dissolved in water and its ligand field splitting energy was measured as 55.0 kJ. What is the color of the complex?