calculate mole fraction of solute in 2M Aqueous solution of acetic acid .the density of solution is 1.02gram/ml.
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Expert's answer
2012-07-03T08:43:47-0400
the solution molarity is c = n(acetic acid) / V(solution) the one liter of solution has mass: m(solution) = d(solution) * V(solution) = 1.02 g/mL * 1000 mL = 1020 g the mass of acetic acid is m(acetic acid) = n(acetic acid) * M(acetic acid) = 2 mol * 60 g/mol = 120 g the mass of water is m(water) = m(solution) - m(acetic acid) = 1020 - 120 = 900 g the quantity of water is n(water) = m(water) / M(water) = 900 g / 18 g/mol = 50 mol the mole fraction of solute (acetic acid) is x = n(acetic acid) / ( n(acetic acid) + n(water) ) = 2 mol / 52 mol = 0.0385
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