Answer to Question #10740 in Inorganic Chemistry for faisal

Question

A student pipets 20 mL of a 0.0187 M solution of KBr into a 250 mL volumetric flask and dilutes to the mark. What is the concentration of the resulting solution?

Answer 1

n(KBr) = C(KBr-initial solution)*V(pipet) = 0.0187 M * 0.02 L = 0.000374
mol
C(KBr-resulting solution) = n(KBr) / V(flask) = 0.000374 mol / 0.25 L =
0.001496 M