A 42.657 g sample of an aqueous NaCl solution at 30.0C was added to a calorimeter whose heat capacity was 7.50 cal/C. Then 43.578 g of water (specific heat--> 1.00 cal/g*C) at 70.0C was added to the calorimeter, and the system allowed to come to equilibrium. If the final temperature was 49.6C, then what is the specific heat (in cal/g*C.) of the NaCl solution?
heat lost by hot water = -(heat gained by NaCl solution + heat gained by the calorimeter)
after simple math specific heat of the NaCl solution is: