Answer to Question #91585 in General Chemistry for Robyn

Question #91585
6g of metal M reacts completely with 23.66g of Chlorine to form 29.66g of the metallic chloride. find the empirical formula of the metallic chloride. (M=27, Cl=35.5)
Expert's answer

According to the law of equivalents:

@$m(M) : m(Cl_2) = M_{eq}(M) : M_{eq}(Cl_2)@$@$M_{eq} (Cl_2) = m(Cl_2)/z = 71/2 = 35.5 mol@$@$6 : 23.66 = M_{eq}(M) : 35.5@$@$M_{eq}(M) = 9 g/mol@$

If the molar mass of the metal element is 27, then the equivalence number:

@$z(M) = 27/9 = 3@$

@$z(Cl_2) = 2@$

@$z(Cl) = 1@$

Then the empirical formula of metal chloride:

@$MCl_3@$

Answer: MCl3

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