Answer to Question #89688 in General Chemistry for Kaleb

General Chemistry

Question #89688

How many grams of KMnO4 are in 3.4L

Expert's answer

"m(solution) =V(solution)*\u03c1(solution)"

"m(KMnO4)=\\dfrac{m(solution)*w(KMnO4,\\%)}{100\\%}"

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