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Answer to Question #89688 in General Chemistry for Kaleb

Question #89688
How many grams of KMnO4 are in 3.4L
Expert's answer

@$m(solution) =V(solution)*ρ(solution)@$

@$m(KMnO4)=\dfrac{m(solution)*w(KMnO4,\%)}{100\%}@$

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