"n(Na2HPO4)=\\dfrac{1g}{141,96g\/mol}=0.007moles"
"N(Na2HPO4)=0.007moles*6.02*10^{23}=4.214*10^{21}molecules"
Na2HPO4"\\leftrightarrow" 2Na++H++PO4 3-
total number of ions="4.214*10^{21}*4=1.69*10^{22}"
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