Question #57733

30cm of hydrogen diffuses out in 2 seconds. How long will it take 90cm of oxygen to diffuse out under the same conditions

Expert's answer

According to Graham's law:

rateH22 x MH2 = rateO22 x MO2

M (H2)=2 g/mol

M (O2) = 32 g/mol

RateH2: 30/2=15 cm/s.

RateO2=(rateH22 x MH2 )/MO2

RateO2=(152 x 2 )/32 = 14.1 cm/s

So that 90 cm of oxygen under the same conditions will be diffused during:

T=90/14.1=6.4 s

rateH22 x MH2 = rateO22 x MO2

M (H2)=2 g/mol

M (O2) = 32 g/mol

RateH2: 30/2=15 cm/s.

RateO2=(rateH22 x MH2 )/MO2

RateO2=(152 x 2 )/32 = 14.1 cm/s

So that 90 cm of oxygen under the same conditions will be diffused during:

T=90/14.1=6.4 s

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