Answer to Question #57733 in General Chemistry for Tyrone
rateH22 x MH2 = rateO22 x MO2
M (H2)=2 g/mol
M (O2) = 32 g/mol
RateH2: 30/2=15 cm/s.
RateO2=(rateH22 x MH2 )/MO2
RateO2=(152 x 2 )/32 = 14.1 cm/s
So that 90 cm of oxygen under the same conditions will be diffused during:
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